Question

calculate the energy transferred when 2 A current flow through a 10 ohm resistor for 30 minutes​

Answer 1

Explanation:

Energy transferred,

E = I^2 RT

I = current flow = 2A

R = resistance = 10 ohm

T=time taken = 30 min =1800 s

E = 2^2 × 10 × 1800 J

E = 4×10×1800

E =72000 J

E = 72 kJ