Question

calculate the energy transferred when 2A current flows through a 10 ohm resistor for 30 minutes​

Answer 1

Answer:

72 kJ

Explanation:

I = 2 A R = 10 Ω t = 30 min = 1800 s

J = R × I² × t

= 10 × 2² × 1800

= 72000 J = 72 kJ

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