Question

Calculate the energy values of the electron in second and third orbits of hydrogen atom.
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Answer 1

Hello

ANSWER

The energy of the electron in the second and third Bohr's orbitals of the hydrogen atom is -5.42×10-12erg and -2.42×10-12erg respectively ,Calculate the wavelength of the emitted radiation when the electron drop from the third to the second orbit.

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Answer 2

The energy values of the electron in second and third orbits of hydrogen atom is $-5.448 \times 10^{-19}$ J and $- 2.41 \times 10^{-12}$ J

Explanation:

Formula: The energy of an electron with principal quantum number be,

Eₙ = - (Z² * k) ÷ n²

Where Z = atomic number

k = Bohr constant, k = 2.179 * 10⁻¹⁸ J

n - number of the energy level

For hydrogen atom Z = 1, for an electron in the second orbit n = 2

E₂ = - (1² * 2.179 *  10⁻¹⁸) ÷ 2²  = $-5.448 \times 10^{-19}$ J

For hydrogen atom Z = 1, for an electron in the second orbit n = 3

E₃ = - (1² * 2.179 *  10⁻¹⁸) ÷ 3²  = $- 2.41 \times 10^{-12}$ J

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