Question

Calculate the enthalpy change of the reaction :

CH2Cl2(g) → C(g) + 2H(g) + 2Cl(g)

Average bond enthalpy of C-H bond is 414 kJ/mol and
C-Cl bond is 330 kJ/mol.​

Answer 1

Answer:

answer is 1488 kj/mol

Explanation:

bond break

2 c-h

2 c-cl

enthalpy=bond break - bond formed

= (0×414+2×330)-0

= 828-660

=1488 kj/mol.

These is answer