Calculate the enthalpy change on freezing of 1mole at10°c to
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ΔH =Cp .ΔT (for changing 1mol of liquid water from 10 -0 degree celcius)
=75.3 x10 = .753kj
from (
0 to 10)
36.8 x-10 =- .368kj
Total enthalpy change= .753 +(-6.03) + (-.368)
=-5.645kjmol-1
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