Question

Calculate the enthalpy change when 2.38g of carbon monoxide vaporize at the normal boiling point. Enthalpy of vapororization of co is 6.04 kj mol-1

Answer 1

Answer:

Answer : The enthalpy change is 0.5134 KJ.

Solution : Given,

Mass of carbon monoxide = 2.38 g

Enthalpy of vaporization = 6.04 KJ/mole

Molar mass of carbon monoxide = 28 g/mole

The enthalpy change when 28 g carbon monoxide vaporizes at normal boiling point = 6.04 KJ/mole

and The enthalpy change for 2.38 g of carbon monoxide vaporizes at normal boiling point = \frac{6.04KJ/mole\times 2.38g}{28g}=0.5134KJ

28g

6.04KJ/mole×2.38g

=0.5134KJ

Therefore, the enthalpy change is 0.514 KJ.