Question

Calculate the enthalpy of formation of benzene using the following data.
CH6C(l)+15/2O2 (g) ----> 6 CO2 (g) + 3H20(l)
∆cHº = – 3266 kj
C(s) + O2(g) → CO2(g)
∆Hº = – 393.1 kj
H2(g)+1/202 (g) → H2O(l)
∆H° = – 286.0 kj​

Answer 1

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