Question

calculate the enthalpy
of formation of propane(C3 H8) if its enthalpy of combustion is -2280 kJ mol-1. Given enthalpy of formation of CO2 and H2O are -393.5 and -286.1 kJ respectively​

Answer 1

Answer:

c3h8 5o2 ----- 4h2o +3 co2

Explanation:

5*co2 Del HF+4*Del hf--del h f c3h8= -2280

solve now you will get the answer use sign accorndingly