Question

Calculate the enthalpy of hydrogenation of c2h2 into c2h4. Bond energies for c

Answer 1

Answer:

The bond enthalpy is the energy needed to break up the bond.

You can estimate the enthalpy of reaction from the difference of the bonds braked minus the enthalpies of the bonds formed. You can simply take the difference all the bonds in the reactants and products. The enthalpies of bonds, which remain unchanged will cancel out:

The components have the following bonds

C₂H₂ one C≡C and two C-H

H₂ one H-H

C₂H₄ one C=C and four C-H

Hence the heat of reaction is:

ΔHr = Hb(C≡C) + 2·Hb(C-H) + Hb(H-H) - Hb(C=C) - 4·Hb(C-H)

= Hb(C≡C) + Hb(H-H) - Hb(C=C) - 2·Hb(C-H)

= 839kJ/mol + 436kJ/mol - 614kJ/mol - 2·(413kJ/mol)

= -165kJ/mol

Answer 2

Answer:

Ans is -163.9

Explanation:

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