Question

Calculate the enthalpy of the following reaction.

4NH3 + 5O2 ------> 6H2O + 4NO

Standard enthalpies of formation at 298 K for NH3,H2O and NO are -46.1,-242 and -90.4 kJ/mole.​

Answer 1

✔✔✔Here is your attachment ✔✔✔

Answer 2

⭐《ANSWER》

$\huge\mathfrak{\underline {\underline\pink {ANSWER}}}$

↪Actually welcome to the concept of the THERMOCHEMISTRY

↪Here the Enthalpy is counted as

↪SUMISSION of enthalpies of product - SUMISSION Enthalpies of Reactants ,

↪so we can get as