Calculate the entropy change for conversion of two moles of ice into water at 274 K and into steam at 350 K at 1 atm. pressure. ( ∆Hf = 7KJ\Mole, ∆ Hvap= 45 KJ\Mole)
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Answer:
Entropy change =
T
b
ΔH
vap
×m
m=18 g(1 mole of H
2
O=18 g of H
2
O)
∴ Entropy change =
373
2.257×10
3
×18
⟹ Entropy change =108.9 JK
−1
Explanation:
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