Question

Calculate the entropy change in the melting of 1 Kg of ice at 00C. Heat of fusion of ice s 334.72 Jg-1.​

Answer 1

Answer:

1 calorie = 4.184J, so

the heat of fusion of ice Hf = 80(4.184) = 334.72J/g (or 334.72kJ/kg)

The enthalpy change ΔH = m•Hf where m = mass, H is heat of fusion

So ΔH = 1(334.72) = 334.72kJ

Explanation:

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Answer 2

Answer:

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