Question

Calculate the entropy change involved in conversion of one mole (18g)of solid ice to 273k to liquid water at the same temperature (leatent heat of fusion =6025j mol)

Answer 1

Answer:22.07J/K mol

Explanation:Look at the attachment for explanation

Answer 2

The Change in entropy  for conversion of one mole of ice to  liquid water at 273 K would be 22.069 J K⁻¹ mol⁻¹.

1) Given data is Δfus H = 6025 J/ mol.

  T = 273 K.

2) The Entropy Change can be calculated by using the formula ( ΔS = Δfus H/ T)

3) Substituting the values of Δfus H and T in the above equation gives ΔS = 6025/273 J K⁻¹ mol⁻¹.

ΔS = 22.069 J K⁻¹ mol⁻¹.