Question

Calculate the entropy in the melting of 1g of ice at 0°C in CGS as welll in S. I units..
latent heat of fusion of ice = 80cal. g-1

solve
help plzzzzz​

Answer 1

$\huge\sf{Basic\:Concept}$

★For irreversible spontaneous process=ΔS>0

★For reversible spontaneous process=ΔS=0

★For non- spontaneous process = ΔS<0

$\huge\sf{Solution}$

ΔH(fusion)= Latent heat of fusion of ice= 80 cal.g

$\boxed{\sf{CGS\:unit}}$

$s(fusion) = \frac{h(fusion)}{t(fusion)} \\ = > \frac{80 \: cal. {g}^{ - 1} }{(0 + 273)k} \\ = > 0.293cal. {g}^{ - 1} . {k}^{ - 1}$

$\boxed{\sf{S.I\:units}}$

$s(fusion) = \frac{h(fusion)}{t(fusion)} \\ = > \frac{(80cal. {g}^{ - 1}) \times (100g. {kg}^{ - 1} ) \times (4.184 j. {cal}^{ - 1} }{(0 + 273)k} \\ = > 1225.91j. {kg}^{ - 1}.{k}^{ - 1}$

Answer 2

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$\huge\color{red}\star\star{Hey mate:}\star\star$

$\huge\color{red}\star\star{Thank you.}\star\star$

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