Question

calculate the entropy incress in the evaporation of 1 mole of water 100 degrees Celsius laten heat of evaporation of water at 100 degrees is 540 cal/g.​

Answer 1

Answer:

Explanation:

Solution:- (A) 26cal/mol−K

As  we know that,

ΔS=  

T

ΔH

​  

 

ΔH=540cal/g

Mol. wt. of water =18g

ΔH  

(per mole)

​  

=ΔH  

(per gm)

​  

×Mol. wt.

ΔH  

(per mole)

​  

=540×18=9720cal/mol

Now, as we know that,

ΔS=  

T

ΔH

​  

 

Given T=100℃=(273+100)=373K

∴ΔS=  

373

9720

​  

=26cal/(mol.K)

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