Calculate the equation of the straight line that has a slope of -1/2 and passes through the point (2. -2) )
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Answered by
0
Answer:
we can use slope point form
y-y1=m(x-x1)
where (X1,y1)know points and m is known slope
so y-(-2)=-1/2(x-2)
y+2=0 is required equation
Answered by
0
Step-by-step explanation:
Given:Slope=1
Point is (1,2)
Equation of the line is y−y
1
=m(x−x
1
)
y−2=1(x−1)
⇒y−2=x−1
⇒x−y−1+2=0
∴Equation of the line is x−y+1=0
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