Calculate the equilibrium constant for the cell reaction, where the ∆G° is -212.3 KJ/mol.
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ΔG=nFE
∘
=−2×96500×0.236=−45.548kJ
logK=
2.303RT
nFE
∘
=
0.0591
2×0.236
=7.986
K=(10)
7.986
=96827785.6
=9.68×10
7
∘
=−2×96500×0.236=−45.548kJ
logK=
2.303RT
nFE
∘
=
0.0591
2×0.236
=7.986
K=(10)
7.986
=96827785.6
=9.68×10
7
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