Question

Calculate the equilibrium constant for the reaction
H2 (g) + CO2 (g) ⇔ H2O(g) + CO (g)
At 1395 K, if the equilibrium constants at 1395 K for the following are
2H2O(g)⇔2H2(g) + O2(g) K1= 2.1 * 10^-13
2CO2(g)⇔2CO(g) + O2(g) K2= 1.4 × 10 ^-12

Answer 1

Answer:

k =( k2/k1)

k = (1.4×10^-12/2.1×10^-13)

k = (20/3)

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