Question

Calculate the equivalent capacitance between the points A and B in the
following Figure
С1
C3
CA
Р
R
A.
ell
B
2 uF
3 uF
5 UF
10 uF​

Answer 1

Answer:

they are short in the circuit and the corresponding circuit is shown in figure.

The equivalent capacitance on right parallel branch is C

eq

=

C+C

CC

+C=(3/2)C.

Now all the capacitors are in series so equivalent capacitance across A and B is

C

AB

=(1/C+1/C+1/C+2/3C+1/C)

−1

=(4/C+2/3C)

−1

=(14/3C)

−1

=3C/14

solution

Answer 2

Answer:

3c/14 is the right answer