Question

Calculate the equivalent concentration of a solution of sulfuric acid when dissolving 4.9 g of H2SO4 in a 250 ml solution.​

Answer 1

Answer:

0.2 molar (mol/Liters)

Explanation:

4.9 g H2SO4/(98.079 g/mol H2SO4) = 0.05 mol H2SO4

M= 0.05 mol H2SO4

V=(250 mL) (L/1000 mL)=0.25 Liters

Molarity= M/V=0.05/0.25=0.2 molar

Molarity=0.2 molar (mol/Liters)

Answer 2

Answer:

Molarity, M=

volume(L)

no. of moles

Volume, V=250mL=0.25L

No. of moles, n= mass/molar mass

Mass = 49 g

Molar mass of H

2

SO

4

= 98 g

n=49/98=0.5

M=0.5/0.250=2M

Hence, option A is correct.