Question

calculate the equivalent flow of three resistors 12 ohm , 18 ohm , 36 ohm when they are connected in parellel

Answer 1

• R_1=12ohm
• R_2=18ohm
• R_3=36ohm

We know

$\boxed{\sf \dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}}$

$\\ \sf\longmapsto \dfrac{1}{R}=\dfrac{1}{12}+\dfrac{1}{18}+\dfrac{1}{36}$

$\\ \sf\longmapsto \dfrac{1}{R}=\dfrac{3+2+1}{36}$

$\\ \sf\longmapsto \dfrac{1}{R}=\dfrac{6}{36}$

$\\ \sf\longmapsto R=\dfrac{36}{6}$

$\\ \sf\longmapsto R=6\Omega$