calculate the equivalent mass of cu+2hgno3=ag+cu(no3)2
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Molar mass of Cu = 63.546 g/mol
Molar mass of Ag = 107.87 g/mol
According to the given equation, mole ratio Cu : Ag = 1 : 2
No. of moles of Cu reacted = (22.67 g) / (63.546 g/mol) = 0.35675 mol
No. of moles of Ag formed = (0.35675 mol) × 2 = 0.7135 mol
Mass of Ag formed = (0.7135 mol) × (107.87 g) = 76.97 g
====
OR:
(22.67 g Cu) × (1 mol Cu / 63.546 g Cu) × (2 mol Ag / 1 mol Cu) × (107.87 g Ag / 1 mol Ag)
= 97.67 g Ag
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