Question

Calculate the equivalent resistance between the
points A and B in the following combination.
20 ohm
10 ohm
20 ohm
6 ohm

Answer 1

Explanation:

the fig gives the proper explanation

Answer 2

Answer:

The equivalent resistance between points A and B is 11 Ω.

Explanation:

The three resistors of value 20Ω,10Ω, and 20Ω are connected in parallel and the resultant of this parallel combination is connected in series with 6Ω.

First, let's find the equivalent resistance of a parallel combination. i.e.

$\frac{1}{R_p}=\frac{1}{20}+\frac{1}{10}+\frac{1}{20}=\frac{1+2+1}{20} =\frac{4}{20}=\frac{1}{5}$

$R_p=5\Omega$         (1)

Now the total equivalent resistance of the combination,

$R_e_q_v=R_p+6\Omega$      (2)

By substituting the value of Rp in equation (2) we get;

$R_e_q_v=5\Omega+6\Omega=11\Omega$

Hence, the equivalent resistance between points A and B is 11 Ω.