Calculate the equivalent resistance for the following :
Answers
1. First diagram.
100 ohms and 25 ohms connected to B, are in parallel.
So equivalent resistance = R1 = 25*100/125 = 20 Ohms
R1 is in series with 100 ohms. SO R2 = 120 Ohms.
This R2 and 120 ohms connected to B are in parallel.
Equivalent of these two = 120/2 = 60 ohms.
This 60 is in series with 100 Ohms. So 160 Ohms.
160 Ohms and 40 are in parallel between A and B.
Net : 40*160/(40+160) = 32 Ohms. ANSWER
2.
30 Ohms and 40 Ohms are in series. So 70 Ohms.
That is in parallel with 20 Ohms and 10 Ohms
So we get 1/R = 1/20 + 1/10 + 1/70 = 23/140 => R = 140/23 Ohms
R is in series with 50 Ohms. So we get 140/23 + 50 = 1290/23 ohms
This is parallel with 60 ohms.
So : 1/R = 1/60 + 23/1290 = (43+46) /2580 = 89/2580
R = 2580/89 = 29 ohms approx