calculate the equivalent resistance from the following combination
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Hey
The 2 ohm and 3 ohm resistors are in parallel therefore
Equivalent resistance b/w them is 1/2+1/3 =5/6.
Now 5 ohm and 4 ohm are in series therefore
Equivalent resistance = 4+5 =9
Now we are knowing that the 5/6 ohm resistor and 9 ohm resistor are in parallel therefore
Equivalent resistance = 5/6 + 9 = 5+54/6 = 59/6 ohm.
Hope this helps. :)
pls mark me brainliset.
The 2 ohm and 3 ohm resistors are in parallel therefore
Equivalent resistance b/w them is 1/2+1/3 =5/6.
Now 5 ohm and 4 ohm are in series therefore
Equivalent resistance = 4+5 =9
Now we are knowing that the 5/6 ohm resistor and 9 ohm resistor are in parallel therefore
Equivalent resistance = 5/6 + 9 = 5+54/6 = 59/6 ohm.
Hope this helps. :)
pls mark me brainliset.
Answered by
3
HEY DEAR...
HERE'S YOUR ANSWER ⬇
Let's name the resistors as :
2ohm resistor = R1.
3 ohm resistor = R2.
4 ohm resistor = R3.
5 ohm resistor = R4.
Add the values of R3 and R4.
Total resistance in series = R3+R4.
R3+R4 = 4+5 = 9 ohm.
Refering to fig.1.
We have 3 resistors parallel to each other.
See the pic for the rest of the answer.
Any doubts, please ask me in the comments.
I HOPE YOU FIND IT HELPFUL.
@ LB :)
HERE'S YOUR ANSWER ⬇
Let's name the resistors as :
2ohm resistor = R1.
3 ohm resistor = R2.
4 ohm resistor = R3.
5 ohm resistor = R4.
Add the values of R3 and R4.
Total resistance in series = R3+R4.
R3+R4 = 4+5 = 9 ohm.
Refering to fig.1.
We have 3 resistors parallel to each other.
See the pic for the rest of the answer.
Any doubts, please ask me in the comments.
I HOPE YOU FIND IT HELPFUL.
@ LB :)
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