Question

Calculate the equivalent resistance in the following circuit. 2Ω -----------wwww--------- -----------wwww--------- 6Ω 24 V

Answer 1

equivalent resistance = 2 ohm + 6 ohm

= 8 ohm

= 24/8

= 3 ohm

Answer 2

Given: R₁ = 2

           R₂ = 6

           Potential difference = 24V

To find: Equivalent resistance of he circuit

Solution: According to the question the two resistances are in series. In case of resistance is in series, then the current will flow equally in both resistance, and the potential difference will be distributed such that the sum of both potential differences will be equal to the emf of the cell.

V = V₁ + V₂

Where V is the potential difference, V₁ is the potential difference across resistor 1, and V₂ is the potential difference across resistor 2.

Since V = IR ( Where I is the total current, and R is the resultant resistance.

Therefore, the resultant resistance in case of series connection will be R = R₁ +R₂

R₁ = 2Ω, R₂ = 6Ω

Therefore, resultant resistance will be = ( 2 + 6 )Ω

                                                                = 8Ω

Therefore, the resultant resistance is 8Ω