Question

Calculate the equivalent resistance of the combination of three resistors of 5,10,30 ohm joined In parallel ​

Answer 1

Answer:

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Answer 2

Answer :- 0.3 ohm

Eplanation :-

Given :- The three resistor are in parallel connection.

Let the resistor be :-

$\bold{R_{1} = \: 5, R_{2} = \: 10 \: and \: R_{3} = 30}$

Formulae for finding the equivalent resistant in parallel connection :-

$\large \bold{\frac{1}{ R_{p}} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}}}$

$\large \bold{\frac{1}{ R_{p}} = \frac{1}{5} + \frac{1}{10} + \frac{1}{30}}$

$= \large \bold{\frac{6 + 3 + 1}{30} }$

= 10/30

= 1/3

= 0.3 ohm

∴ The equivalent resistance in parallel connection of the given resistor is 0.3 ohm.

⇒ Law of Parallel connection states that the reciprocal of effective resistance in parallel combination is equal to the sum of reciprocal of individual resistance.