Question

Calculate the equivalent resistance of the following network:


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Answer 1

Answer:

Explanation:

Since two resistors of 20 ohms each are in parallel,

$\frac{1}{R_n}$ = $\frac{1}{R_1}$ + $\frac{1}{R_2}$

$\frac{1}{R_n}$ = $\frac{1}{20}$ + $\frac{1}{20}$

$\frac{1}{R_n}$ = $\frac{1}{10}$

$R_n$ = 10

This is connected with 10 ohm in series

$R$ = $R_1 + R_2$

= 20 ohms