Question

Calculate the equivalent resistance of the following network

Answer 1

Answer:

Explanation:

1/Rp=1/20+1/20

Rp=10

Two resistors are in parallel connection and 1 resistor are in 10 ohm.

So, now in circuit 2 resistor of 10 ohm is present

So, Req = 10+10=20 ohm

So, 20 ohm is the equivalent resistance.

Answer 2

Given,

A figure with a combination of resistors.

To FInd,

The equivalent resistance of the circuit.

Solution,

The formula for calculating the equivalent resistance when resistors are connected in parallel is

1/R' = 1/R₁+1/R₂+....

And when resistors are connected in series

R' = R₁+R₂+...

Now, the resistors of 20 Ω are connected in parallel

So,

1/R' = 1/20+1/20

1/R' = 2/20

R' = 10 Ω

Now, R' and 10 Ω resistor is connected in series

Rnet = R'+10

Rnet = 10+10 = 20 Ω

Hence, the equivalent resistance of the given network is 20 Ω.