Question

Calculate the equivalent resistance of the network across the
points A and B shown in figure.
​

Answer 1

Answer:

Both the 4 ohm resistances are are in series so the equivalent resistance will be 8 ohm (4+4).

Also both the 8 ohm resistances are also in series so equivalent resistance is 16 ohms (8+8).

Now the 16 ohm resistance and 8 ohm resistance (considering resistances from previous two lines) are in parallel. So equivalent resistance will be

$\frac{1}{8} + \frac{1}{16 } = \frac{2 + 1}{16} = \frac{3}{16}$

Now reciprocal of 3/16 is 16/3.

Finally the answers is 5.33 ohms

Hope this helps you...

plzz give me a thanks...

and plzz mark it brainliest...