Question

calculate the equivalent resistance of the network shown......​

Answer 1

Answer:

13.67

Explanation:

equivalent resistance = 5+2+(1/3+1/3) +6

=13 + 2/3

= 13+0.67

= 13.67

Answer 2

Answer:

14.5 ohm

Explanation:

Let

5ohm = R1

2ohm = R2

3ohm = R3

3ohm = R4

6ohm = R5

Now,

R1 and R2 is in series,

R3 and R4 is in parallel, and R5 is in series.

Restisance(in series)(Rs) = R1 + R2 + R3 + R4 + .........

Resistance(in parallel)(1/Rp) = (1/R1) + (1/R2) + (1/R3) +........

therefore, Resistance(in series) = R1 + R2 = 5 + 2 = 7ohm---1

Resistance(in parallel)(1/Rp) = (1/3) + (1/3) = (2/3)

Therefore Rp = (3/2) = 1.5ohm----2

Now,

From eq.1 and eq.2, we get

Total Resistance(Rs) = 7 + 1.5 + 6 = 14.5ohm

Therefore, total resistance of the system is 14.5 ohm