Question

calculate the equivalent resistance of two resistance 4resistance and 16 resistance when they are connected in parallel

Answer 1

1 / rp = 1/ r1 + 1/r2
1/ rp = 1/ 4 + 1/ 16
1/ rp = 4 + 1 / 16
1/rp = 5 / 16 ohm
rp = 16 / 5 ohm
rp, = 3.2 ohm

Answer 2

Answer : 3.2 Ω

In a parallel combination, where the equivalent resistance is R

⇒ 1/R = 1/R₁ + 1/R₂ + ..... + 1/Rₙ

Here the mention two resistors have 4 ohm and 16 ohm resistance. Therefore,

• R₁ = 4 Ω

• R₂ = 16 Ω

So, 1/R = 1/4 + 1/16

⇒ 1/R = (4 + 1)/16

⇒ 1/R = 5/16 Ω

By cross muliplication we get,

⇒ R = 16/5 Ω or 3.2 Ω