Question

Calculate the equivalent weight of H3PO4 in the following reaction:
Ca(OH)2+H3PO4 CaHPO4+2H2O​

Answer 1

Answer: 49

Explanation:

Here No of H in H3P04 is 3 initially

When the reaction takes place its losses 2 of its H + ions

Hence the bascicity of H3PO4 is 2

So the eq weight of an acid

=Molecular weight÷basicity

=98÷2 =49