Calculate the equivalent weight of k2so4 in k4fecn6
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Potassium sulphate = K2SO4 --> 2K^+ + SO4^2- molecular weight = 174.3 (2x39.1 + 32.1 + 4x16)
Equivalent weight = molecular weight/charge on cation or anion = 87.1 g
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U need to find the valence factor first for the Fe in K4[Fe(CN)6] .
Oxidation state of Fe is => +2
Valence factor = 3 – 2 = 1
Eq. Weight = M/1 = M
Equivalent weight = molecular weight/charge on cation or anion = 87.1 g
✔✔✔✔✔✔✔✔✔✔✔
U need to find the valence factor first for the Fe in K4[Fe(CN)6] .
Oxidation state of Fe is => +2
Valence factor = 3 – 2 = 1
Eq. Weight = M/1 = M
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