calculate the equivalent weight of KMno4 in acidic alkaline and neutral medium by available oxygen method , oxidation number method and electron method
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The Mn in KMnO4 exists in +7 state. In Acidic medium, This Mn+7 goes to Mn+2 state and hence there is a net gain of 5 electrons. so, eq wt = 158/5 = 31.6 g.
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