calculate the escape velocity from the Moon the mass of moon is 7.4 into 10 raise to the power 22 kg and radius of the moon is 1740 km
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Answer:
ur answer is above in the fig.
ans= 2.4 x 10^3 m/s
hope it helps
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The escape velocity from the moon is 2.4 km/sec
Given-
- Mass of the moon is = 7.4 × 10²² kg
- Radius of the moon = 1740 km
We know that from the formula of escape velocity
V escape =
where G is the gravitational constant and its value is 6.7 × 10⁻¹¹ N-m² /kg²
M is the mass which is given and R is the radius, which is also given.
By substituting all the values we get
V escape = √ 2 × 6.7 × 10⁻¹¹ × 7.4 × 10²² / 1740 × 10³
V escape = 2366.4 m/sec
V escape = 2.366 km/sec ≈ 2.4 km/sec
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