Question

Calculate the escape velocity of a body from the surface of the earth. [Given : G = 6.67 x 10⁻¹¹ Nm²/kg², R = 6400 km, g = 9.8 m/s²]
(Ans. 11.2 km/s)

Answer 1

Escape velocity =$\sqrt{ \frac{2GM}{R} }$

But You have only provided me,
G = Gravitational constant
R = Radius from centre

You should provide us M = Mass

Answer 2

Dear Tejas,

◆ Answer -

ve = 11.2 km

● Explanation -

Escape velocity is calculated by formula -

ve = √(2GM/R)

ve = √(2 × 6.67×10^-11 × 6×10^24 / 6.4×10^6)

ve = √(1.254×10^8)

ve = 1.12×10^4 m/s

ve = 11.2 km

Hence, escape velocity of satellite from earth surface is 11.2 km.

Thanks dear. Hope this is helpful..