Question

calculate the escape velocity on the surface of the moon given the mass and radius of the moon to be 7.34*10^22kg and 1.74*10^6 m respectively

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Answer 1

Step-by-step explanation:

Mass (m)=7.34×10

22

Radius (R)=1.74×10 6

V e = R2GMV e

= 1.74×10 6

6.67×10 −11 ×7.34×10 22 V e

= 1.74×10 6

48.98716×10 11V e

= 28.1535×10 5v e

=1.68×10 3 m/sec