Question

calculate the escape velocity on the surface of the moon given the mass and radius of moon to be 7.34×10raise to the power 22 kg and 1.74×10 rase to the power 6m respectively​

Answer 1

the formula of escape velocity is..........√2GM/R

u can put the values and calculate .....it would give u approx 2.3Km/s

Answer 2

The escape velocity on the surface of Moon is 2372.2 m/s.

Explanation:

The formula of is given by :

$v=\sqrt{\dfrac{2GM}{R}}$

We have,

Mass of Moon, $M=7.34\times 10^{22}\ kg$

Radius of Moon, $R=1.74\times 10^6\ m$

The escape velocity becomes :

$v=\sqrt{\dfrac{2GM}{R}}\\\\v=\sqrt{\dfrac{2\times 6.67\times 10^{-11}\times 7.34\times 10^{22}}{1.74\times 10^6}}\\\\v=2372.2\ m/s$

So, the escape velocity on the surface of Moon is 2372.2 m/s.

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