Question

calculate the excess pressure inside a soap bubble of radius 4mm . surface tension of soap solutions is 25 × 10^-3 N/m at 20°c?



Help plz​

Answer 1

Explanation:

• Surface Tension (s) = 25 × 10-³ N/m
• Radius (r) = 4 mm = 4 × 10 -³ m
• Excess pressure (p) = ?

$p \: = \frac{4 \: s}{r}$

$p \: = \: \frac{4 \times 25 \times {10}^{ - 3} }{4 \times {10}^{ - 3} }$

$p \: = 25 \: pascal$