Question

Calculate the f.p of aquaous solution containing 10.5 in 200gm of water assume completing dissociation of magnism bromide (molar mass=184) kf = 1.86​

Answer 1

Answer:

(Molar mass of magnesium bromide =184 g mol ^(-1) ... Complete dissociation. Hence i=3. W8=10.5g ... T0A-TS=3×0.931.86×10.5×51000184×200× 102

Answer 2

Answer:

Given mass of solute (Wa) = 10.5 gm

Molecular mass of solute (Ma) = 184 gm/mol

Give mass of solvent i.e. H2O (Wb) = 200 gm

Freezing point of water (T°) = 273.15 K

Freezing point of solution (Tf) = ?

Therefore, freezing point of aqueous solution of MgBr2 is 271.56 K.