Physics, asked by aarthimeenat, 7 months ago

Calculate the Fermi energy of Cu at 0K if the concentration of electron is 8.5×1028 m–3

Answers

Answered by Anonymous
5

Answer:

So the energy given to an electron by the electric field by 100 volts applied to a 1 meter copper wire would be on the order of W=eEd = 100 volts x 40 nm = 0.000004 eV.

Explanation:

Try to solve using this way

Answered by NainaRamroop
0

Given:

concentration (n) of the Cu = 8.5 × 10²⁸  {m}^{ - 3}

To Find:

The Fermi energy of Cu at 0K.

Solution:

  • Fermi energy refers to the maximum kinetic energy that can be attained by the atoms at 0K.
  • It can be mathematically represented as:

Ef =  \frac{ {h}^{2} }{8m}  {( \frac{3n}{\pi} )}^{ \frac{2}{3} }

where,

h = 6.63 × 10^-34 Js (Planck's constant)

mass of electron = 9.11 × 10^-31 kg

n (concentration) = 8.5 × 10²⁸ m^-3

  • Put the above values in the formula of Ef to find the Fermi energy

 =  \frac{ {h}^{2} }{8m}  {( \frac{3n}{\pi} )}^{ \frac{2}{3} }

  = \frac{ {6.63 \times  {10}^{ - 34} }^{2} }{8 \times 9.11 \times  {10}^{ - 31} }  {( \frac{3(8.5 \times  {10}^{28} }{\pi} )}^{ \frac{2}{3} }

 = 1.1307 \times  {10}^{ - 18} j

  • Now convert this to eV

1 joule = 6.242 × 10¹⁸ Electron volts

1.1307 × 10^-18 joule = 1.1307 × 10^-18 × 6.242 × 10¹⁸ eV

                                 = 7.0578 eV

Hence, the Fermi Energy of Cu at 0k is 7.0578 eV.

#SPJ3

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