Question

Calculate the field due to an electric dipole of length 10 cm and consisting of charges ±100 µC

at a point 20 cm from each charge.

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Answer 1

Answer:

In the file attached.

Explanation:

Thank you.

Answer 2

Answer:

Concept:

The separation of opposite electrical charges inside a system, or the system's overall polarity, is measured by the electric dipole moment. The coulomb-meter (Cm) is the SI unit for the electric dipole moment. Another unit of measurement in atomic physics and chemistry is the debye (D). Although practical dipoles have separated charges, the first-order element of the multipole expansion theoretically defines an electric dipole as two equal and opposite fees that are infinitesimally close to one another.

Given:

Calculate the field caused by a 10 cm long electric dipole with 100 C charges at a location 20 cm from each charge.

Find:

find the answer for the given question

Answer:

The electric dipole moment is calculated using the formula p = qd, where q is the distance between the two charges and q is their magnitude.

The size of the electric field produced by a point charge Q is determined by this equation. The distance r in the denominator is the separation between the point of interest and the point charge, Q, or the centre of a spherical charge.

Electric field at an axial position for a short dipole is inversely proportional to the third power of the distance between the dipole's centre and the point. As a result, the electric field will be reduced by a factor of 1/8th times if the distance doubles.

$E_{2} =\frac{kq}{(20*10^{-2})^{2} }$

    $=\frac{k(100*10^{-6} }{(2*10^{-1})^{2} }$

    $=\frac{k}{4*(10^{-2}) }$

    $=\frac{k}{400}$

$k=\frac{1}{4} \pi$ε₀

$E=2E_{1} sin$θ

   $=\frac{2(k/400)}{(5/20)}$

   $=\frac{k}{800}$     $(k=\frac{1}{4} \pi$ε₀$)$

$E=\frac{1}{3200} \pi$ε₀

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