Question

Calculate the final temperature of a monatomic ideal gas that is compress reversible and material from 16 litre

Answer 1

Final temperature is 1200 K

Explanation:

Given ,

$V_1$ = 16 ltr

let assume that,

$V_2$ = 2 ltr

$T_1$ = 300 K

Final temperature ,$T_2$ = ?

We know that,

$T\times V^{\gamma - 1}$ = constant

∴ $\frac{T_2}{T_1} = (\frac{V_1}{V_2})^{\gamma - 1}$

  $T_2 = T_1\times (\frac{V_1}{V_2})^{\gamma - 1}$$T_2 = 300\times (\frac{16}{2})^{1.6666 - 1)$

$T_2 = 1200$  K