Calculate the final temperature of water when 2 kg of water at 80dagree is mixed with 8kg of water at20 dagee
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Heat lost by hot water = mSdT
= 2 kg × 1 cal/(g °C) × (T - 80) °C
Heat gained by cold water = m’SdT’
= 8 kg × 1 cal/(g °C) × (20 - T) °C
Heat lost by hot water = Heat gained by cold water
2 kg × 1 cal/(g °C) × (T - 80) °C = 8 kg × 1 cal/(g °C) × (20 - T) °C
T - 80 = 80 - 4T
5T = 160
T = 32 °C
Temperature of mixture is 32 °C
= 2 kg × 1 cal/(g °C) × (T - 80) °C
Heat gained by cold water = m’SdT’
= 8 kg × 1 cal/(g °C) × (20 - T) °C
Heat lost by hot water = Heat gained by cold water
2 kg × 1 cal/(g °C) × (T - 80) °C = 8 kg × 1 cal/(g °C) × (20 - T) °C
T - 80 = 80 - 4T
5T = 160
T = 32 °C
Temperature of mixture is 32 °C
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