Calculate the final velocity of block sliding from rest position to position A on a horizontal surface. When 100 N applied on block, the block moves from rest position to position A is 4 m. Coefficient of friction between surface and block is My = 0.2 Mass of block is 10 kg and acceleration due to gravity is 10 m/s2. Rest position 4 m Position A A) 4 m/s B) 8 m/s c) 2 m/s D) 16 m/s
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answer:
8m/s
Net force = force - friction
friction =Meu * mass * g
= 0.2*10*10= 20N
net force = 100-20
= 80N
acceleration =force /mass
= 80/10=8m/s^2
v^2=u^2 +2as
v^2 = 0+ 2*8*4( rest means acceleration is zero)
v^2 = 64
v= 8m/s
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