Question

calculate the final velocity when a body moves from rest & attains an acceleration of 5m/sec² covering a distance of 50 meters

Answer 1

calculate the final velocity when a body moves from rest & attains an acceleration of 5m/sec² covering a distance of 50 meters

Solution :
   
Initially body is at rest , hence initial velocity is Zero .
Acceleration = 5 m / sec^2
Distance traveled =  50 meters.
We Know that
   V² - U² = 2as
Where V = final velocity  ,
U = initial velocity 
a = Acceleration of the body
s= Distance Covered

V² - 0² = 2*5*50
 V² = 500
V = √(500)
V = 10√5
Hence the Final Velocity of the body is 10√5 .

HOpe this helps You!!!
 

Answer 2

TO find final velocity:

Given- distance- 50 meters
          acceleration-5m/s
          initial velocity(u)-0
          
the formula is v^2-u^2=2as 

So, v^2-u^2=2as
 
      v^-0=2*5*50
      v^-0=500
      v=500^
so square root of 500 is 22.360
  so the Final velocity(v) is 22.360