Chemistry, asked by dragonstac2726, 1 year ago

Calculate the final volume of gas 'X' ,if the pressure of the gas,originally at S.T.P .is doubled and its temperature is made three times.

Answers

Answered by sandeep189
11
Assume the volume at STP to be V and Pressure to be P and temperature to be T
The number of moles of the gas X present , n = PV/RT  (ideal gas equation, PV = nRT)
The second set of conditions denoted by subscript 2,
P2 = 2P
T2= 3T
V2 = nRT2P2
Substituting the values of T2and P2
V2 =P×V×R×3TR×T×2PV2 = 3 × V2= 1.5 V

So, the final volume will be 1.5 fold the original volume.
Answered by Anonymous
23
\underline\bold{\huge{SOLUTION\: \: :}}

\boxed{INITIAL\:\:CONDITIONS\:\: :}

◼ P1 = 760 mm Hg

◼ V1 = V1 (say)

◼ T1 = 273 K

\boxed{FINAL\:\:CONDITIONS\:\: :}

◼ P2 = (2×760) mm Hg

◼ V2 = V2 (say)

◼ T2 = (3×273) K

______________________________

NOW, USING THE GAS EQUATION :

______________________________

P1V1/T1 = P2V2/T2

=> (760×V1)/273 = (1520×V2)/819

=> V2 = 1.5 V1

SO, the final volume is 1.5 times the initial volume of the gas at S. T. P. [ANSWER]
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