Calculate the final volume of one mole of an ideal gas initially at 0°C and 1 atm pressure, if it absorbs 100 cal heat during a reversible isothermal expansion.
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Answer:
The gas is in the standard temperature and pressure condition i.e. at S.T.P
Therefore,
Vi=22.4dm3
Vf=?
As given that the expansion is isothermal and reversible
∴ΔU=0
Now from first law of thermodynamics,
ΔU=q+w
∵ΔU=0
∴q=–w
Given that the heat is absorbed.
∴q=1000cal
⇒w=−q=−1000cal
Now,
Work done in a reversible isothermal expansion is given by-
w=−nRTln(ViVf)
Given:-
T=0℃=273K
n=1 mol
∴1000=−nRTln(ViVf)
⇒1000=−1×2.303×2×273×log(22.4Vf)
⇒log(22.4Vf)=−2.303×273×21000
⇒
Explanation:
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