Question

Calculate the first and second velocities of the car with four washers attached to the pulley, using the formulas
v1 = 0.25 m / t1 , and v2 = 0.25 m / (t2 – t1)
where t1 and t2 are the average times the car took to reach the 0.25 and the 0.50 meter marks. Record these velocities, to two decimal places, in Table E.
What is the first velocity of the car with four washers at the 0.25 meter mark?
(Answer)
m/s What is the second velocity of the car with four washers at the 0.50 meter mark?
(Answer)
m/s

Answer 1

Answer:

0.28

0.56

Explanation:

if you're doing this on edge this is the right answer

Answer 2

Answer:

Velocities are calculated.

Explanation:

• After a certain length of time, the speed altered. The formula for this is speed = $\frac{d1}{t1}$

• We get 65$\frac{mi}{h}$ = $\frac{130mi}{t1}$ by substituting variables.

• In the meantime, the value of t1 is 2.0 hours.

• As a result, the time is represented as t2 = T - t1 = 3.33 h — 2.0 h = 1.33 h at lower speeds.

• This also provides us the difference between the two speeds, for example, speed = $\frac{d2}{t2}$ = 73 mi.

• D = d1 + d2 = 130 miles + 73 miles = 203 miles.

• $\frac{d}{t}$ = $\frac{203mi}{3.33h}$ = 61 $\frac{mi}{h}$ is the normal speed.

Because the speed is unusual (65 $\frac{mi}{h}$ + 55 $\frac{mi}{h}$), The two rates were not maintained keep up with the times.

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